std::allocator::deallocate
void deallocate( T* p, std::size_t n ); | ? | ? |
|---|
分配指针引用的存储。p，它必须是以前调用的指针。allocate()...
争论n必须等于调用allocate()原产p否则，行为就没有定义。
打电话::operator delete(void*)，但未具体说明何时和如何调用它。
参数
p | - | pointer obtained from allocate() |
|---|---|---|
n | - | number of objects earlier passed to allocate() |
返回值
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另见
allocate | allocates uninitialized storage (public member function) |
|---|---|
deallocate static | deallocates storage using the allocator (public static member function of std::allocator_traits) |
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