std::basic_stringstream::str
std::basic_string<CharT,Traits,Allocator> str() const; | (1) | ? |
|---|---|---|
void str(const std::basic_string<CharT,Traits,Allocator>& new_str); | (2) | ? |
管理基础字符串对象的内容。
1%29返回基础字符串的副本，就像通过调用rdbuf()->str()...
2%29替换基础字符串的内容，就像通过调用rdbuf()->str(new_str)...
参数
new_str | - | new contents of the underlying string |
|---|
返回值
1%29基础字符串对象的副本。
2%29%28%29。
注记
返回的基础字符串的副本。str是一个临时对象，它将在表达式末尾被解构，因此直接调用c_str()关于…的结果str()%28，例如auto *ptr = out.str().c_str();%29导致一个悬空指针。
例
二次
#include <sstream>
#include <iostream>
int main()
{
int n;
std::istringstream in; // could also use in("1 2")
in.str("1 2");
in >> n;
std::cout << "after reading the first int from \"1 2\", the int is "
<< n << ", str() = \"" << in.str() << "\"\n";
std::ostringstream out("1 2");
out << 3;
std::cout << "after writing the int '3' to output stream \"1 2\""
<< ", str() = \"" << out.str() << "\"\n";
std::ostringstream ate("1 2", std::ios_base::ate);
ate << 3;
std::cout << "after writing the int '3' to append stream \"1 2\""
<< ", str() = \"" << ate.str() << "\"\n";
}二次
产出：
二次
after reading the first int from "1 2", the int is 1, str() = "1 2"
after writing the int '3' to output stream "1 2", str() = "3 2"
after writing the int '3' to append stream "1 2", str() = "1 23"二次
另见
str | replaces or obtains a copy of the associated character string (public member function of std::basic_stringbuf) |
|---|
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