std::bit_not
Defined in header <functional> | ? | ? |
|---|---|---|
template< class T = void > struct bit_not; | ? | (since C++14) |
函数对象，用于按位执行NOT。有效呼叫operator~论类型T...
专门性
The standard library provides a specialization of std::bit_not when T is not specified, which leaves the parameter types and return type to be deduced. bit_not<void> function object implementing ~x deducing argument and return types (class template specialization) | bit_not<void> | function object implementing ~x deducing argument and return types (class template specialization) | (since C++14) |
|---|---|---|---|
bit_not<void> | function object implementing ~x deducing argument and return types (class template specialization) |
成员类型
Type | Definition |
|---|---|
result_type(deprecated in C++17) | T |
argument_type(deprecated in C++17) | T |
成员函数
operator() | returns the result of bitwise NOT of its argument (public member function) |
|---|
STD：BIT[医]否：：操作员%28%29
constexpr T operator()( const T& arg ) const; | ? | ? |
|---|
按位返回的结果arg...
参数
arg | - | value to compute bitwise NOT of |
|---|
返回值
结果~arg...
例外
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可能的实施
常数T算子%28%29%28 const T&Arg%29 Const{Ref~Arg；}
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