std::minus
Defined in header <functional> | ? | ? |
---|---|---|
template< class T > struct minus; | ? | (until C++14) |
template< class T = void > struct minus; | ? | (since C++14) |
函数对象,用于执行减法。有效呼叫operator-
关于类型的两个实例T
...
专门性
The standard library provides a specialization of std::minus when T is not specified, which leaves the parameter types and return type to be deduced. minus<void> function object implementing x - y deducing argument and return types (class template specialization) | minus<void> | function object implementing x - y deducing argument and return types (class template specialization) | (since C++14) |
---|---|---|---|
minus<void> | function object implementing x - y deducing argument and return types (class template specialization) |
成员类型
Type | Definition |
---|---|
result_type(deprecated in C++17) | T |
first_argument_type(deprecated in C++17) | T |
second_argument_type(deprecated in C++17) | T |
成员函数
operator() | returns the difference between two arguments (public member function) |
---|
STD::减::操作员%28%29
T operator()( const T& lhs, const T& rhs ) const; | ? | (until C++14) |
---|---|---|
constexpr T operator()( const T& lhs, const T& rhs ) const; | ? | (since C++14) |
返回lhs
和rhs
...
参数
lhs, rhs | - | values to subtract from one another |
---|
返回值
结果lhs - rhs
...
例外
%280%29
可能的实施
ConstT算子%28%29%28 const T&lhs,const T&rhs%29 const{返回lhs-rhs;}
*。
? cppreference.com
在CreativeCommonsAttribution下授权-ShareAlike未移植许可v3.0。
本文档系腾讯云开发者社区成员共同维护,如有问题请联系 cloudcommunity@tencent.com