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There are three basic operations performed using references: assigning by reference, passing by reference, and returning by reference. This section will give an introduction to these operations, with links for further reading.
Assign By Reference
In the first of these, PHP references allow you to make two variables refer to the same content. Meaning, when you do:
<?php
$a?=&?$b;
?>it means that $a and $b point to the same content.
Note: $a and $b are completely equal here. $a is not pointing to $b or vice versa. $a and $b are pointing to the same place.
Note: If you assign, pass, or return an undefined variable by reference, it will get created. Example #1 Using references with undefined variables <?php function?foo(&$var)?{?} foo($a);?//?$a?is?"created"?and?assigned?to?null $b?=?array(); foo($b['b']); var\_dump(array\_key\_exists('b',?$b));?//?bool(true) $c?=?new?StdClass; foo($c->d); var\_dump(property\_exists($c,?'d'));?//?bool(true) ?>
The same syntax can be used with functions that return references, and with the new operator (since PHP 4.0.4 and before PHP 5.0.0):
<?php
$foo?=&?find_var($bar);
?> Since PHP 5, new returns a reference automatically, so using =& in this context is deprecated and produces an E_DEPRECATED message in PHP 5.3 and later, and an E_STRICT message in earlier versions. As of PHP 7.0 it is syntactically invalid. (Technically, the difference is that, in PHP 5, object variables, much like resources, are a mere pointer to the actual object data, so these object references are not "references" in the same sense used before (aliases). For more information, see Objects and references.)
Warning
If you assign a reference to a variable declared global inside a function, the reference will be visible only inside the function. You can avoid this by using the $GLOBALS array.
Example #2 Referencing global variables inside functions
<?php
$var1?=?"Example?variable";
$var2?=?"";
function?global_references($use_globals)
{
????global?$var1,?$var2;
????if?(!$use_globals)?{
????????$var2?=&?$var1;?//?visible?only?inside?the?function
????}?else?{
????????$GLOBALS["var2"]?=&?$var1;?//?visible?also?in?global?context
????}
}
global_references(false);
echo?"var2?is?set?to?'$var2'\n";?//?var2?is?set?to?''
global_references(true);
echo?"var2?is?set?to?'$var2'\n";?//?var2?is?set?to?'Example?variable'
?>Think about global $var; as a shortcut to $var =& $GLOBALS'var';. Thus assigning another reference to $var only changes the local variable's reference.
Note: If you assign a value to a variable with references in a foreach statement, the references are modified too. Example #3 References and foreach statement <?php $ref?=?0; $row?=&?$ref; foreach?(array(1,?2,?3)?as?$row)?{ ????//?do?something } echo?$ref;?//?3?-?last?element?of?the?iterated?array ?>
While not being strictly an assignment by reference, expressions created with the language construct array() can also behave as such by prefixing & to the array element to add. Example:
<?php
$a?=?1;
$b?=?array(2,?3);
$arr?=?array(&$a,?&$b[0],?&$b[1]);
$arr[0]++;?$arr[1]++;?$arr[2]++;
/*?$a?==?2,?$b?==?array(3,?4);?*/
?>Note, however, that references inside arrays are potentially dangerous. Doing a normal (not by reference) assignment with a reference on the right side does not turn the left side into a reference, but references inside arrays are preserved in these normal assignments. This also applies to function calls where the array is passed by value. Example:
<?php
/*?Assignment?of?scalar?variables?*/
$a?=?1;
$b?=&?$a;
$c?=?$b;
$c?=?7;?//$c?is?not?a?reference;?no?change?to?$a?or?$b
/*?Assignment?of?array?variables?*/
$arr?=?array(1);
$a?=&?$arr[0];?//$a?and?$arr[0]?are?in?the?same?reference?set
$arr2?=?$arr;?//not?an?assignment-by-reference!
$arr2[0]++;
/*?$a?==?2,?$arr?==?array(2)?*/
/*?The?contents?of?$arr?are?changed?even?though?it's?not?a?reference!?*/
?>In other words, the reference behavior of arrays is defined in an element-by-element basis; the reference behavior of individual elements is dissociated from the reference status of the array container.
Pass By Reference
The second thing references do is to pass variables by reference. This is done by making a local variable in a function and a variable in the calling scope referencing the same content. Example:
<?php
function?foo(&$var)
{
????$var++;
}
$a=5;
foo($a);
?>will make $a to be 6. This happens because in the function foo the variable $var refers to the same content as $a. For more information on this, read the passing by reference section.
Return By Reference
The third thing references can do is return by reference.
← What References Are
What References Are Not →
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